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14353113 = 319251809
BaseRepresentation
bin110110110000…
…001011011001
31000000012202210
4312300023121
512133244423
61231345333
7232666545
oct66601331
930005683
1014353113
118113785
124982249
132c87088
141c98a25
1513d7b93
hexdb02d9

14353113 has 8 divisors (see below), whose sum is σ = 20144800. Its totient is φ = 9065088.

The previous prime is 14353111. The next prime is 14353121. The reversal of 14353113 is 31135341.

14353113 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14353113 - 21 = 14353111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14353113.

It is not an unprimeable number, because it can be changed into a prime (14353111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 125848 + ... + 125961.

It is an arithmetic number, because the mean of its divisors is an integer number (2518100).

Almost surely, 214353113 is an apocalyptic number.

It is an amenable number.

14353113 is a deficient number, since it is larger than the sum of its proper divisors (5791687).

14353113 is a wasteful number, since it uses less digits than its factorization.

14353113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 251831.

The product of its digits is 540, while the sum is 21.

The square root of 14353113 is about 3788.5502504256. The cubic root of 14353113 is about 243.0237406736.

Adding to 14353113 its reverse (31135341), we get a palindrome (45488454).

The spelling of 14353113 in words is "fourteen million, three hundred fifty-three thousand, one hundred thirteen".

Divisors: 1 3 19 57 251809 755427 4784371 14353113