143540131123 has 2 divisors, whose sum is σ = 143540131124. Its totient is φ = 143540131122.

The previous prime is 143540131103. The next prime is 143540131129. The reversal of 143540131123 is 321131045341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 143540131123 - 2³³ = 134950196531 is a prime.

It is a super-2 number, since 2×143540131123² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143540131091 and 143540131100.

It is not a weakly prime, because it can be changed into another prime (143540131129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71770065561 + 71770065562.

It is an arithmetic number, because the mean of its divisors is an integer number (71770065562).

Almost surely, 2^143540131123 is an apocalyptic number.

143540131123 is a deficient number, since it is larger than the sum of its proper divisors (1).

143540131123 is an equidigital number, since it uses as much as digits as its factorization.

143540131123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 143540131123 its reverse (321131045341), we get a palindrome (464671176464).

The spelling of 143540131123 in words is "one hundred forty-three billion, five hundred forty million, one hundred thirty-one thousand, one hundred twenty-three".