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14354124354035 = 531205187451331
BaseRepresentation
bin1101000011100001010001…
…1110111011000111110011
31212211020111121101001020122
43100320110132323013303
53340134221313312120
650310105501000455
73011023403606444
oct320702436730763
955736447331218
1014354124354035
114634605a94194
121739b1325312b
1380178513393b
14378a599852cb
1519d5b508ca25
hexd0e147bb1f3

14354124354035 has 16 divisors (see below), whose sum is σ = 17780718799872. Its totient is φ = 11112791685600.

The previous prime is 14354124354029. The next prime is 14354124354107. The reversal of 14354124354035 is 53045342145341.

It is a de Polignac number, because none of the positive numbers 2k-14354124354035 is a prime.

It is a super-2 number, since 2×143541243540352 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31578320 + ... + 32029650.

It is an arithmetic number, because the mean of its divisors is an integer number (1111294924992).

Almost surely, 214354124354035 is an apocalyptic number.

14354124354035 is a deficient number, since it is larger than the sum of its proper divisors (3426594445837).

14354124354035 is a wasteful number, since it uses less digits than its factorization.

14354124354035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 656554.

The product of its (nonzero) digits is 1728000, while the sum is 44.

Adding to 14354124354035 its reverse (53045342145341), we get a palindrome (67399466499376).

The spelling of 14354124354035 in words is "fourteen trillion, three hundred fifty-four billion, one hundred twenty-four million, three hundred fifty-four thousand, thirty-five".

Divisors: 1 5 31 155 205187 451331 1025935 2256655 6360797 13991261 31803985 69956305 92607253897 463036269485 2870824870807 14354124354035