14354311222081 has 2 divisors, whose sum is σ = 14354311222082. Its totient is φ = 14354311222080.

The previous prime is 14354311222067. The next prime is 14354311222093. The reversal of 14354311222081 is 18022211345341.

14354311222081 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12377590512400 + 1976720709681 = 3518180^2 + 1405959^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14354311222081 is a prime.

It is a super-2 number, since 2×14354311222081² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14354311222081.

It is not a weakly prime, because it can be changed into another prime (14354311222481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177155611040 + 7177155611041.

It is an arithmetic number, because the mean of its divisors is an integer number (7177155611041).

Almost surely, 2^{14354311222081} is an apocalyptic number.

It is an amenable number.

14354311222081 is a deficient number, since it is larger than the sum of its proper divisors (1).

14354311222081 is an equidigital number, since it uses as much as digits as its factorization.

14354311222081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46080, while the sum is 37.

The spelling of 14354311222081 in words is "fourteen trillion, three hundred fifty-four billion, three hundred eleven million, two hundred twenty-two thousand, eighty-one".