Base | Representation |
---|---|
bin | 1101000011100100111101… |
… | …1111000011110100100011 |
3 | 1212211100001121000201221012 |
4 | 3100321033133003310203 |
5 | 3340143233221323121 |
6 | 50310352021451135 |
7 | 3011060053546232 |
oct | 320711737036443 |
9 | 55740047021835 |
10 | 14355114245411 |
11 | 4634a73833235 |
12 | 173a14a870aab |
13 | 8018b2241994 |
14 | 378b11220b19 |
15 | 19d621e23c5b |
hex | d0e4f7c3d23 |
14355114245411 has 2 divisors, whose sum is σ = 14355114245412. Its totient is φ = 14355114245410.
The previous prime is 14355114245393. The next prime is 14355114245513. The reversal of 14355114245411 is 11454241155341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14355114245411 - 242 = 9957067734307 is a prime.
It is not a weakly prime, because it can be changed into another prime (14355114242411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177557122705 + 7177557122706.
It is an arithmetic number, because the mean of its divisors is an integer number (7177557122706).
Almost surely, 214355114245411 is an apocalyptic number.
14355114245411 is a deficient number, since it is larger than the sum of its proper divisors (1).
14355114245411 is an equidigital number, since it uses as much as digits as its factorization.
14355114245411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 192000, while the sum is 41.
The spelling of 14355114245411 in words is "fourteen trillion, three hundred fifty-five billion, one hundred fourteen million, two hundred forty-five thousand, four hundred eleven".
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