Base | Representation |
---|---|
bin | 10100111001100000100… |
… | …001000110000001111001 |
3 | 12002021220221200221200122 |
4 | 110321200201012001321 |
5 | 142012202410140144 |
6 | 3015430341143025 |
7 | 205520563454633 |
oct | 24714041060171 |
9 | 5067827627618 |
10 | 1436138365049 |
11 | 504076737893 |
12 | 1b23bb9baa75 |
13 | a5572921b2b |
14 | 4d71bd9da53 |
15 | 27555b037ee |
hex | 14e60846079 |
1436138365049 has 2 divisors, whose sum is σ = 1436138365050. Its totient is φ = 1436138365048.
The previous prime is 1436138365027. The next prime is 1436138365087. The reversal of 1436138365049 is 9405638316341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1322286108649 + 113852256400 = 1149907^2 + 337420^2 .
It is a cyclic number.
It is not a de Polignac number, because 1436138365049 - 212 = 1436138360953 is a prime.
It is a super-2 number, since 2×14361383650492 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1436138365019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 718069182524 + 718069182525.
It is an arithmetic number, because the mean of its divisors is an integer number (718069182525).
Almost surely, 21436138365049 is an apocalyptic number.
It is an amenable number.
1436138365049 is a deficient number, since it is larger than the sum of its proper divisors (1).
1436138365049 is an equidigital number, since it uses as much as digits as its factorization.
1436138365049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5598720, while the sum is 53.
The spelling of 1436138365049 in words is "one trillion, four hundred thirty-six billion, one hundred thirty-eight million, three hundred sixty-five thousand, forty-nine".
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