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143630122113601 is a prime number
BaseRepresentation
bin100000101010000101111110…
…011010000101101001000001
3200211112220110011102210021121
4200222011332122011221001
5122311213442230113401
61225250433414152241
742152635215113314
oct4052057632055101
9624486404383247
10143630122113601
114184621355a282
1214138591352681
13621b354649b56
142767a40bbc97b
151191238298ca1
hex82a17e685a41

143630122113601 has 2 divisors, whose sum is σ = 143630122113602. Its totient is φ = 143630122113600.

The previous prime is 143630122113593. The next prime is 143630122113623. The reversal of 143630122113601 is 106311221036341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128323561344001 + 15306560769600 = 11327999^2 + 3912360^2 .

It is a cyclic number.

It is not a de Polignac number, because 143630122113601 - 23 = 143630122113593 is a prime.

It is a super-2 number, since 2×1436301221136012 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (143630122113671) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71815061056800 + 71815061056801.

It is an arithmetic number, because the mean of its divisors is an integer number (71815061056801).

Almost surely, 2143630122113601 is an apocalyptic number.

It is an amenable number.

143630122113601 is a deficient number, since it is larger than the sum of its proper divisors (1).

143630122113601 is an equidigital number, since it uses as much as digits as its factorization.

143630122113601 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 34.

Adding to 143630122113601 its reverse (106311221036341), we get a palindrome (249941343149942).

The spelling of 143630122113601 in words is "one hundred forty-three trillion, six hundred thirty billion, one hundred twenty-two million, one hundred thirteen thousand, six hundred one".