143630124432241 has 4 divisors (see below), whose sum is σ = 146686084526592. Its totient is φ = 140574164337892.

The previous prime is 143630124432229. The next prime is 143630124432247. The reversal of 143630124432241 is 142234421036341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 143630124432241 - 2¹³ = 143630124424049 is a prime.

It is a super-2 number, since 2×143630124432241² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143630124432194 and 143630124432203.

It is not an unprimeable number, because it can be changed into a prime (143630124432247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1527980047105 + ... + 1527980047198.

It is an arithmetic number, because the mean of its divisors is an integer number (36671521131648).

Almost surely, 2^{143630124432241} is an apocalyptic number.

It is an amenable number.

143630124432241 is a deficient number, since it is larger than the sum of its proper divisors (3055960094351).

143630124432241 is an equidigital number, since it uses as much as digits as its factorization.

143630124432241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3055960094350.

The product of its (nonzero) digits is 331776, while the sum is 40.

Adding to 143630124432241 its reverse (142234421036341), we get a palindrome (285864545468582).

The spelling of 143630124432241 in words is "one hundred forty-three trillion, six hundred thirty billion, one hundred twenty-four million, four hundred thirty-two thousand, two hundred forty-one".