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143640254256041 is a prime number
BaseRepresentation
bin100000101010001111011010…
…010101001001001110101001
3200211120212121021211221202102
4200222033122111021032221
5122311400220042143131
61225255231041143145
742153444255651224
oct4052173225111651
9624525537757672
10143640254256041
114184a542919914
121413a53a62aab5
13621c2aa822cca
1427683226dc5bb
15119162ca5a1cb
hex82a3da5493a9

143640254256041 has 2 divisors, whose sum is σ = 143640254256042. Its totient is φ = 143640254256040.

The previous prime is 143640254256019. The next prime is 143640254256217. The reversal of 143640254256041 is 140652452046341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 143448624816016 + 191629440025 = 11977004^2 + 437755^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143640254256041 is a prime.

It is a super-2 number, since 2×1436402542560412 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (143640254256011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71820127128020 + 71820127128021.

It is an arithmetic number, because the mean of its divisors is an integer number (71820127128021).

Almost surely, 2143640254256041 is an apocalyptic number.

It is an amenable number.

143640254256041 is a deficient number, since it is larger than the sum of its proper divisors (1).

143640254256041 is an equidigital number, since it uses as much as digits as its factorization.

143640254256041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2764800, while the sum is 47.

The spelling of 143640254256041 in words is "one hundred forty-three trillion, six hundred forty billion, two hundred fifty-four million, two hundred fifty-six thousand, forty-one".