Base | Representation |
---|---|
bin | 1101000100000111101110… |
… | …0110111100111010100011 |
3 | 1212212020010211110001111201 |
4 | 3101001323212330322203 |
5 | 3340321340234240441 |
6 | 50314533520222031 |
7 | 3011540216133265 |
oct | 321017346747243 |
9 | 55766124401451 |
10 | 14364444446371 |
11 | 4638a21456318 |
12 | 173bb1346a917 |
13 | 80273b235356 |
14 | 37935842bb35 |
15 | 19d9bb0c7c31 |
hex | d107b9bcea3 |
14364444446371 has 2 divisors, whose sum is σ = 14364444446372. Its totient is φ = 14364444446370.
The previous prime is 14364444446333. The next prime is 14364444446383. The reversal of 14364444446371 is 17364444446341.
It is a strong prime.
It is an emirp because it is prime and its reverse (17364444446341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14364444446371 - 27 = 14364444446243 is a prime.
It is not a weakly prime, because it can be changed into another prime (14364444446311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7182222223185 + 7182222223186.
It is an arithmetic number, because the mean of its divisors is an integer number (7182222223186).
Almost surely, 214364444446371 is an apocalyptic number.
14364444446371 is a deficient number, since it is larger than the sum of its proper divisors (1).
14364444446371 is an equidigital number, since it uses as much as digits as its factorization.
14364444446371 is an evil number, because the sum of its binary digits is even.
The product of its digits is 37158912, while the sum is 55.
The spelling of 14364444446371 in words is "fourteen trillion, three hundred sixty-four billion, four hundred forty-four million, four hundred forty-six thousand, three hundred seventy-one".
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