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14365227055513 is a prime number
BaseRepresentation
bin1101000100001010101001…
…0000010111100110011001
31212212022011101001201102111
43101002222100113212121
53340324441111234023
650315143314232321
73011565501165505
oct321025220274631
955768141051374
1014365227055513
114639293199134
1217400b15856a1
13802834409599
143793d034b305
1519da14b6700d
hexd10aa417999

14365227055513 has 2 divisors, whose sum is σ = 14365227055514. Its totient is φ = 14365227055512.

The previous prime is 14365227055457. The next prime is 14365227055577. The reversal of 14365227055513 is 31555072256341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8803492516624 + 5561734538889 = 2967068^2 + 2358333^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14365227055513 is a prime.

It is not a weakly prime, because it can be changed into another prime (14365227055913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7182613527756 + 7182613527757.

It is an arithmetic number, because the mean of its divisors is an integer number (7182613527757).

Almost surely, 214365227055513 is an apocalyptic number.

It is an amenable number.

14365227055513 is a deficient number, since it is larger than the sum of its proper divisors (1).

14365227055513 is an equidigital number, since it uses as much as digits as its factorization.

14365227055513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3780000, while the sum is 49.

The spelling of 14365227055513 in words is "fourteen trillion, three hundred sixty-five billion, two hundred twenty-seven million, fifty-five thousand, five hundred thirteen".