143663643101113 has 4 divisors (see below), whose sum is σ = 143951546194000. Its totient is φ = 143375740008228.

The previous prime is 143663643101039. The next prime is 143663643101179. The reversal of 143663643101113 is 311101346366341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 143663643101113 - 2¹⁷ = 143663642970041 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 143663643101113.

It is not an unprimeable number, because it can be changed into a prime (143663643101413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143951545695 + ... + 143951546692.

It is an arithmetic number, because the mean of its divisors is an integer number (35987886548500).

Almost surely, 2^{143663643101113} is an apocalyptic number.

It is an amenable number.

143663643101113 is a deficient number, since it is larger than the sum of its proper divisors (287903092887).

143663643101113 is an equidigital number, since it uses as much as digits as its factorization.

143663643101113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 287903092886.

The product of its (nonzero) digits is 279936, while the sum is 43.

Adding to 143663643101113 its reverse (311101346366341), we get a palindrome (454764989467454).

The spelling of 143663643101113 in words is "one hundred forty-three trillion, six hundred sixty-three billion, six hundred forty-three million, one hundred one thousand, one hundred thirteen".