Base | Representation |
---|---|
bin | 1101000110001100101111… |
… | …0101010101110011111011 |
3 | 1212222122022012222220220021 |
4 | 3101203023311111303323 |
5 | 3341413001413242021 |
6 | 50343200533111311 |
7 | 3014243100360055 |
oct | 321431365256373 |
9 | 55878265886807 |
10 | 14400150134011 |
11 | 4652084380984 |
12 | 1746a19188537 |
13 | 805c0b70a185 |
14 | 37ad845528d5 |
15 | 19e8aaaa0c41 |
hex | d18cbd55cfb |
14400150134011 has 2 divisors, whose sum is σ = 14400150134012. Its totient is φ = 14400150134010.
The previous prime is 14400150133949. The next prime is 14400150134021. The reversal of 14400150134011 is 11043105100441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14400150134011 - 211 = 14400150131963 is a prime.
It is not a weakly prime, because it can be changed into another prime (14400150134021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7200075067005 + 7200075067006.
It is an arithmetic number, because the mean of its divisors is an integer number (7200075067006).
Almost surely, 214400150134011 is an apocalyptic number.
14400150134011 is a deficient number, since it is larger than the sum of its proper divisors (1).
14400150134011 is an equidigital number, since it uses as much as digits as its factorization.
14400150134011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 25.
Adding to 14400150134011 its reverse (11043105100441), we get a palindrome (25443255234452).
The spelling of 14400150134011 in words is "fourteen trillion, four hundred billion, one hundred fifty million, one hundred thirty-four thousand, eleven".
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