1440120314131 has 4 divisors (see below), whose sum is σ = 1446464456712. Its totient is φ = 1433776171552.

The previous prime is 1440120314119. The next prime is 1440120314153. The reversal of 1440120314131 is 1314130210441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1440120314131 - 2⁵ = 1440120314099 is a prime.

It is a super-2 number, since 2×1440120314131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1440120314096 and 1440120314105.

It is not an unprimeable number, because it can be changed into a prime (1440120314231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3172070950 + ... + 3172071403.

It is an arithmetic number, because the mean of its divisors is an integer number (361616114178).

Almost surely, 2^{1440120314131} is an apocalyptic number.

1440120314131 is a deficient number, since it is larger than the sum of its proper divisors (6344142581).

1440120314131 is an equidigital number, since it uses as much as digits as its factorization.

1440120314131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6344142580.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1440120314131 its reverse (1314130210441), we get a palindrome (2754250524572).

The spelling of 1440120314131 in words is "one trillion, four hundred forty billion, one hundred twenty million, three hundred fourteen thousand, one hundred thirty-one".