Base | Representation |
---|---|
bin | 11010110100110000… |
… | …11011001011101010 |
3 | 1101011122111111202022 |
4 | 31122120123023222 |
5 | 213443210112442 |
6 | 10341004504442 |
7 | 1016606432423 |
oct | 153230331352 |
9 | 41148444668 |
10 | 14401254122 |
11 | 6120150412 |
12 | 295ab4b122 |
13 | 148679c258 |
14 | 9a88c664a |
15 | 5944933d2 |
hex | 35a61b2ea |
14401254122 has 4 divisors (see below), whose sum is σ = 21601881186. Its totient is φ = 7200627060.
The previous prime is 14401254061. The next prime is 14401254211. The reversal of 14401254122 is 22145210441.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 22145210441 = 283 ⋅78251627.
It can be written as a sum of positive squares in only one way, i.e., 7286500321 + 7114753801 = 85361^2 + 84349^2 .
It is a super-2 number, since 2×144012541222 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14401254091 and 14401254100.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3600313529 + ... + 3600313532.
Almost surely, 214401254122 is an apocalyptic number.
14401254122 is a deficient number, since it is larger than the sum of its proper divisors (7200627064).
14401254122 is an equidigital number, since it uses as much as digits as its factorization.
14401254122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7200627063.
The product of its (nonzero) digits is 2560, while the sum is 26.
Adding to 14401254122 its reverse (22145210441), we get a palindrome (36546464563).
The spelling of 14401254122 in words is "fourteen billion, four hundred one million, two hundred fifty-four thousand, one hundred twenty-two".
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