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14401254233 is a prime number
BaseRepresentation
bin11010110100110000…
…11011001101011001
31101011122111111220102
431122120123031121
5213443210113413
610341004505145
71016606432642
oct153230331531
941148444812
1014401254233
116120150503
12295ab4b1b5
13148679c312
149a88c66c9
15594493458
hex35a61b359

14401254233 has 2 divisors, whose sum is σ = 14401254234. Its totient is φ = 14401254232.

The previous prime is 14401254211. The next prime is 14401254253. The reversal of 14401254233 is 33245210441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10484121664 + 3917132569 = 102392^2 + 62587^2 .

It is a cyclic number.

It is not a de Polignac number, because 14401254233 - 214 = 14401237849 is a prime.

It is a super-2 number, since 2×144012542332 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14401254196 and 14401254205.

It is not a weakly prime, because it can be changed into another prime (14401254253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7200627116 + 7200627117.

It is an arithmetic number, because the mean of its divisors is an integer number (7200627117).

Almost surely, 214401254233 is an apocalyptic number.

It is an amenable number.

14401254233 is a deficient number, since it is larger than the sum of its proper divisors (1).

14401254233 is an equidigital number, since it uses as much as digits as its factorization.

14401254233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 14401254233 its reverse (33245210441), we get a palindrome (47646464674).

The spelling of 14401254233 in words is "fourteen billion, four hundred one million, two hundred fifty-four thousand, two hundred thirty-three".