Base | Representation |
---|---|
bin | 1000011000011111010… |
… | …0011111110001010011 |
3 | 111202201111010102010111 |
4 | 2012013310133301103 |
5 | 4324414211402142 |
6 | 150054121542151 |
7 | 13255523646445 |
oct | 2060764376123 |
9 | 452644112114 |
10 | 144012606547 |
11 | 560913a88a7 |
12 | 23ab1644957 |
13 | 10770ca87b4 |
14 | 6d82504495 |
15 | 3b2d136e17 |
hex | 2187d1fc53 |
144012606547 has 2 divisors, whose sum is σ = 144012606548. Its totient is φ = 144012606546.
The previous prime is 144012606509. The next prime is 144012606557. The reversal of 144012606547 is 745606210441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144012606547 - 211 = 144012604499 is a prime.
It is a super-4 number, since 4×1440126065474 (a number of 46 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (144012606557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72006303273 + 72006303274.
It is an arithmetic number, because the mean of its divisors is an integer number (72006303274).
Almost surely, 2144012606547 is an apocalyptic number.
144012606547 is a deficient number, since it is larger than the sum of its proper divisors (1).
144012606547 is an equidigital number, since it uses as much as digits as its factorization.
144012606547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 161280, while the sum is 40.
Adding to 144012606547 its reverse (745606210441), we get a palindrome (889618816988).
The spelling of 144012606547 in words is "one hundred forty-four billion, twelve million, six hundred six thousand, five hundred forty-seven".
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