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144013222435 = 5371807743063
BaseRepresentation
bin1000011000011111011…
…0110110001000100011
3111202201112021200222011
42012013312312020203
54324414341104220
6150054143053351
713255532123155
oct2060766661043
9452645250864
10144013222435
11560917895a5
1223ab18a1257
1310771162c24
146d82624ad5
153b2d20965a
hex2187db6223

144013222435 has 16 divisors (see below), whose sum is σ = 177500506176. Its totient is φ = 112087974528.

The previous prime is 144013222433. The next prime is 144013222517. The reversal of 144013222435 is 534222310441.

It is a cyclic number.

It is not a de Polignac number, because 144013222435 - 21 = 144013222433 is a prime.

It is a super-2 number, since 2×1440132224352 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 144013222397 and 144013222406.

It is not an unprimeable number, because it can be changed into a prime (144013222433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3322714 + ... + 3365776.

It is an arithmetic number, because the mean of its divisors is an integer number (11093781636).

Almost surely, 2144013222435 is an apocalyptic number.

144013222435 is a deficient number, since it is larger than the sum of its proper divisors (33487283741).

144013222435 is a wasteful number, since it uses less digits than its factorization.

144013222435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61182.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 144013222435 its reverse (534222310441), we get a palindrome (678235532876).

The spelling of 144013222435 in words is "one hundred forty-four billion, thirteen million, two hundred twenty-two thousand, four hundred thirty-five".

Divisors: 1 5 37 185 18077 43063 90385 215315 668849 1593331 3344245 7966655 778449851 3892249255 28802644487 144013222435