14401325151 has 16 divisors (see below), whose sum is σ = 22070997600. Its totient is φ = 9269817984.

The previous prime is 14401325149. The next prime is 14401325231. The reversal of 14401325151 is 15152310441.

14401325151 is a `hidden beast` number, since 1 + 4 + 401 + 3 + 251 + 5 + 1 = 666.

It is not a de Polignac number, because 14401325151 - 2¹ = 14401325149 is a prime.

It is a super-2 number, since 2×14401325151² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14401325051) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9195466 + ... + 9197031.

It is an arithmetic number, because the mean of its divisors is an integer number (1379437350).

Almost surely, 2^14401325151 is an apocalyptic number.

14401325151 is a deficient number, since it is larger than the sum of its proper divisors (7669672449).

14401325151 is a wasteful number, since it uses less digits than its factorization.

14401325151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18392535 (or 18392529 counting only the distinct ones).

The product of its (nonzero) digits is 2400, while the sum is 27.

Adding to 14401325151 its reverse (15152310441), we get a palindrome (29553635592).

The spelling of 14401325151 in words is "fourteen billion, four hundred one million, three hundred twenty-five thousand, one hundred fifty-one".