Base | Representation |
---|---|
bin | 100000101111101010111101… |
… | …100001111010110000011011 |
3 | 200212220112211202220112021120 |
4 | 200233222331201322300123 |
5 | 122334004002401020443 |
6 | 1230142505145340323 |
7 | 42222425061551235 |
oct | 4057527541726033 |
9 | 625815752815246 |
10 | 144013433220123 |
11 | 419838326a2a25 |
12 | 1419a9274976a3 |
13 | 6248540580c9c |
14 | 277c404727255 |
15 | 119b1be970083 |
hex | 82fabd87ac1b |
144013433220123 has 8 divisors (see below), whose sum is σ = 193078783397136. Its totient is φ = 95478519261600.
The previous prime is 144013433220001. The next prime is 144013433220131. The reversal of 144013433220123 is 321022334310441.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 144013433220123 - 237 = 143875994266651 is a prime.
It is not an unprimeable number, because it can be changed into a prime (144013433221123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 132609053988 + ... + 132609055073.
It is an arithmetic number, because the mean of its divisors is an integer number (24134847924642).
Almost surely, 2144013433220123 is an apocalyptic number.
144013433220123 is a deficient number, since it is larger than the sum of its proper divisors (49065350177013).
144013433220123 is a wasteful number, since it uses less digits than its factorization.
144013433220123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 265218109245.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 144013433220123 its reverse (321022334310441), we get a palindrome (465035767530564).
The spelling of 144013433220123 in words is "one hundred forty-four trillion, thirteen billion, four hundred thirty-three million, two hundred twenty thousand, one hundred twenty-three".
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