144020212202131 has 4 divisors (see below), whose sum is σ = 147532900304664. Its totient is φ = 140507524099600.

The previous prime is 144020212202123. The next prime is 144020212202177. The reversal of 144020212202131 is 131202212020441.

144020212202131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 144020212202131 - 2³ = 144020212202123 is a prime.

It is a super-2 number, since 2×144020212202131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 144020212202096 and 144020212202105.

It is not an unprimeable number, because it can be changed into a prime (144020212202831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1756344051205 + ... + 1756344051286.

It is an arithmetic number, because the mean of its divisors is an integer number (36883225076166).

Almost surely, 2^{144020212202131} is an apocalyptic number.

144020212202131 is a deficient number, since it is larger than the sum of its proper divisors (3512688102533).

144020212202131 is an equidigital number, since it uses as much as digits as its factorization.

144020212202131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3512688102532.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 144020212202131 its reverse (131202212020441), we get a palindrome (275222424222572).

The spelling of 144020212202131 in words is "one hundred forty-four trillion, twenty billion, two hundred twelve million, two hundred two thousand, one hundred thirty-one".