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144023401321 = 227634464323
BaseRepresentation
bin1000011000100001110…
…1101011001101101001
3111202202020102211202221
42012020131223031221
54324424442320241
6150055145154041
713256014466212
oct2061035531551
9452666384687
10144023401321
11560975010a8
1223ab518b921
13107732b8037
146d83b14409
153b2e06a5d1
hex218876b369

144023401321 has 4 divisors (see below), whose sum is σ = 144657865872. Its totient is φ = 143388936772.

The previous prime is 144023401303. The next prime is 144023401331. The reversal of 144023401321 is 123104320441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 144023401321 - 215 = 144023368553 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144023401331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 317231935 + ... + 317232388.

It is an arithmetic number, because the mean of its divisors is an integer number (36164466468).

Almost surely, 2144023401321 is an apocalyptic number.

It is an amenable number.

144023401321 is a deficient number, since it is larger than the sum of its proper divisors (634464551).

144023401321 is an equidigital number, since it uses as much as digits as its factorization.

144023401321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 634464550.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 144023401321 its reverse (123104320441), we get a palindrome (267127721762).

The spelling of 144023401321 in words is "one hundred forty-four billion, twenty-three million, four hundred one thousand, three hundred twenty-one".

Divisors: 1 227 634464323 144023401321