14403113020561 has 4 divisors (see below), whose sum is σ = 14404657930992. Its totient is φ = 14401568110132.

The previous prime is 14403113020559. The next prime is 14403113020609. The reversal of 14403113020561 is 16502031130441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14403113020561 - 2¹ = 14403113020559 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14403113020531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 772441231 + ... + 772459876.

It is an arithmetic number, because the mean of its divisors is an integer number (3601164482748).

Almost surely, 2^{14403113020561} is an apocalyptic number.

It is an amenable number.

14403113020561 is a deficient number, since it is larger than the sum of its proper divisors (1544910431).

14403113020561 is an equidigital number, since it uses as much as digits as its factorization.

14403113020561 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1544910430.

The product of its (nonzero) digits is 8640, while the sum is 31.

The spelling of 14403113020561 in words is "fourteen trillion, four hundred three billion, one hundred thirteen million, twenty thousand, five hundred sixty-one".