Base | Representation |
---|---|
bin | 1101000110010111110011… |
… | …1000001000000000010011 |
3 | 1212222220222020010122112102 |
4 | 3101211330320020000103 |
5 | 3341440042312243443 |
6 | 50344411400551015 |
7 | 3014406515442314 |
oct | 321457470100023 |
9 | 55886866118472 |
10 | 14403120431123 |
11 | 4653368aa4086 |
12 | 1747507a8246b |
13 | 806292bc1a28 |
14 | 37b186c2660b |
15 | 19e9d1728cb8 |
hex | d197ce08013 |
14403120431123 has 2 divisors, whose sum is σ = 14403120431124. Its totient is φ = 14403120431122.
The previous prime is 14403120431087. The next prime is 14403120431213. The reversal of 14403120431123 is 32113402130441.
Together with next prime (14403120431213) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14403120431123 - 212 = 14403120427027 is a prime.
It is a super-2 number, since 2×144031204311232 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14403120431723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7201560215561 + 7201560215562.
It is an arithmetic number, because the mean of its divisors is an integer number (7201560215562).
Almost surely, 214403120431123 is an apocalyptic number.
14403120431123 is a deficient number, since it is larger than the sum of its proper divisors (1).
14403120431123 is an equidigital number, since it uses as much as digits as its factorization.
14403120431123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 14403120431123 its reverse (32113402130441), we get a palindrome (46516522561564).
The spelling of 14403120431123 in words is "fourteen trillion, four hundred three billion, one hundred twenty million, four hundred thirty-one thousand, one hundred twenty-three".
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