Base | Representation |
---|---|
bin | 10100111101011001110… |
… | …101011001001010101111 |
3 | 12002200201110110122111221 |
4 | 110331121311121022233 |
5 | 142044234212304403 |
6 | 3021401402124211 |
7 | 206026334211133 |
oct | 24753165311257 |
9 | 5080643418457 |
10 | 1440321213103 |
11 | 505922859503 |
12 | 1b31887b0667 |
13 | a5a8b3a3856 |
14 | 4d9d770d3c3 |
15 | 276ece45dbd |
hex | 14f59d592af |
1440321213103 has 16 divisors (see below), whose sum is σ = 1524653020800. Its totient is φ = 1356843428640.
The previous prime is 1440321213073. The next prime is 1440321213139. The reversal of 1440321213103 is 3013121230441.
It is a cyclic number.
It is not a de Polignac number, because 1440321213103 - 213 = 1440321204911 is a prime.
It is a super-3 number, since 3×14403212131033 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1440321213203) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 68697300 + ... + 68718262.
It is an arithmetic number, because the mean of its divisors is an integer number (95290813800).
Almost surely, 21440321213103 is an apocalyptic number.
1440321213103 is a deficient number, since it is larger than the sum of its proper divisors (84331807697).
1440321213103 is a wasteful number, since it uses less digits than its factorization.
1440321213103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41142.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1440321213103 its reverse (3013121230441), we get a palindrome (4453442443544).
The spelling of 1440321213103 in words is "one trillion, four hundred forty billion, three hundred twenty-one million, two hundred thirteen thousand, one hundred three".
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