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144034241333403 = 348011413777801
BaseRepresentation
bin100000101111111110010101…
…110010100100100010011011
3200212222112112221001012112210
4200233332111302210202123
5122334324111240132103
61230200230023410203
742224062525602441
oct4057762562444233
9625875487035483
10144034241333403
11419916402a4463
12141a2973bb3963
13624a4a84bc655
14277d41a08ab91
15119b9db616e03
hex82ff95ca489b

144034241333403 has 4 divisors (see below), whose sum is σ = 192045655111208. Its totient is φ = 96022827555600.

The previous prime is 144034241333401. The next prime is 144034241333413. The reversal of 144034241333403 is 304333142430441.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 144034241333403 - 21 = 144034241333401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144034241333401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24005706888898 + ... + 24005706888903.

It is an arithmetic number, because the mean of its divisors is an integer number (48011413777802).

Almost surely, 2144034241333403 is an apocalyptic number.

144034241333403 is a deficient number, since it is larger than the sum of its proper divisors (48011413777805).

144034241333403 is an equidigital number, since it uses as much as digits as its factorization.

144034241333403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48011413777804.

The product of its (nonzero) digits is 497664, while the sum is 39.

Adding to 144034241333403 its reverse (304333142430441), we get a palindrome (448367383763844).

The spelling of 144034241333403 in words is "one hundred forty-four trillion, thirty-four billion, two hundred forty-one million, three hundred thirty-three thousand, four hundred three".

Divisors: 1 3 48011413777801 144034241333403