Base | Representation |
---|---|
bin | 1000011000100100101… |
… | …0000010010010111011 |
3 | 111202210001022122121021 |
4 | 2012021022002102323 |
5 | 4324440431431303 |
6 | 150100242323311 |
7 | 13256215361521 |
oct | 2061112022273 |
9 | 452701278537 |
10 | 144035030203 |
11 | 560a3024049 |
12 | 23ab9059537 |
13 | 1077582a12c |
14 | 6d854a0311 |
15 | 3b300b5ebd |
hex | 21892824bb |
144035030203 has 2 divisors, whose sum is σ = 144035030204. Its totient is φ = 144035030202.
The previous prime is 144035030179. The next prime is 144035030213. The reversal of 144035030203 is 302030530441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144035030203 - 25 = 144035030171 is a prime.
It is not a weakly prime, because it can be changed into another prime (144035030213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72017515101 + 72017515102.
It is an arithmetic number, because the mean of its divisors is an integer number (72017515102).
Almost surely, 2144035030203 is an apocalyptic number.
144035030203 is a deficient number, since it is larger than the sum of its proper divisors (1).
144035030203 is an equidigital number, since it uses as much as digits as its factorization.
144035030203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 144035030203 its reverse (302030530441), we get a palindrome (446065560644).
The spelling of 144035030203 in words is "one hundred forty-four billion, thirty-five million, thirty thousand, two hundred three".
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