1440404014131 has 6 divisors (see below), whose sum is σ = 2080583575980. Its totient is φ = 960269342748.

The previous prime is 1440404014123. The next prime is 1440404014139. The reversal of 1440404014131 is 1314104040441.

1440404014131 is a `hidden beast` number, since 1 + 440 + 40 + 40 + 14 + 131 = 666.

It is an interprime number because it is at equal distance from previous prime (1440404014123) and next prime (1440404014139).

It is not a de Polignac number, because 1440404014131 - 2³ = 1440404014123 is a prime.

It is a super-2 number, since 2×1440404014131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1440404014095 and 1440404014104.

It is not an unprimeable number, because it can be changed into a prime (1440404014139) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 80022445221 + ... + 80022445238.

It is an arithmetic number, because the mean of its divisors is an integer number (346763929330).

Almost surely, 2^{1440404014131} is an apocalyptic number.

1440404014131 is a deficient number, since it is larger than the sum of its proper divisors (640179561849).

1440404014131 is a wasteful number, since it uses less digits than its factorization.

1440404014131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 160044890465 (or 160044890462 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 27.

Adding to 1440404014131 its reverse (1314104040441), we get a palindrome (2754508054572).

The spelling of 1440404014131 in words is "one trillion, four hundred forty billion, four hundred four million, fourteen thousand, one hundred thirty-one".