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144040521322 = 272020260661
BaseRepresentation
bin1000011000100101111…
…0111110111001101010
3111202210102122122000001
42012021132332321222
54324443333140242
6150101000133214
713256313141565
oct2061136767152
9452712578001
10144040521322
11560a6134665
1223abaa6720a
1310776a00609
146d860cd4dc
153b307eceb7
hex21897bee6a

144040521322 has 4 divisors (see below), whose sum is σ = 216060781986. Its totient is φ = 72020260660.

The previous prime is 144040521217. The next prime is 144040521397. The reversal of 144040521322 is 223125040441.

144040521322 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 223125040441 = 1991121231359.

It can be written as a sum of positive squares in only one way, i.e., 142197622281 + 1842899041 = 377091^2 + 42929^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36010130329 + ... + 36010130332.

Almost surely, 2144040521322 is an apocalyptic number.

144040521322 is a deficient number, since it is larger than the sum of its proper divisors (72020260664).

144040521322 is an equidigital number, since it uses as much as digits as its factorization.

144040521322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72020260663.

The product of its (nonzero) digits is 7680, while the sum is 28.

Adding to 144040521322 its reverse (223125040441), we get a palindrome (367165561763).

The spelling of 144040521322 in words is "one hundred forty-four billion, forty million, five hundred twenty-one thousand, three hundred twenty-two".

Divisors: 1 2 72020260661 144040521322