14404113524011 has 4 divisors (see below), whose sum is σ = 14443361790112. Its totient is φ = 14364865257912.

The previous prime is 14404113523999. The next prime is 14404113524123. The reversal of 14404113524011 is 11042531140441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14404113524011 - 2⁵ = 14404113523979 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14404113524611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19624132500 + ... + 19624133233.

It is an arithmetic number, because the mean of its divisors is an integer number (3610840447528).

Almost surely, 2^{14404113524011} is an apocalyptic number.

14404113524011 is a deficient number, since it is larger than the sum of its proper divisors (39248266101).

14404113524011 is an equidigital number, since it uses as much as digits as its factorization.

14404113524011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39248266100.

The product of its (nonzero) digits is 7680, while the sum is 31.

Adding to 14404113524011 its reverse (11042531140441), we get a palindrome (25446644664452).

The spelling of 14404113524011 in words is "fourteen trillion, four hundred four billion, one hundred thirteen million, five hundred twenty-four thousand, eleven".