14404113525121 has 4 divisors (see below), whose sum is σ = 14868762348544. Its totient is φ = 13939464701700.

The previous prime is 14404113525107. The next prime is 14404113525127. The reversal of 14404113525121 is 12152531140441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14404113525121 - 2¹⁷ = 14404113394049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14404113525127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232324411665 + ... + 232324411726.

It is an arithmetic number, because the mean of its divisors is an integer number (3717190587136).

Almost surely, 2^{14404113525121} is an apocalyptic number.

It is an amenable number.

14404113525121 is a deficient number, since it is larger than the sum of its proper divisors (464648823423).

14404113525121 is an equidigital number, since it uses as much as digits as its factorization.

14404113525121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 464648823422.

The product of its (nonzero) digits is 19200, while the sum is 34.

Adding to 14404113525121 its reverse (12152531140441), we get a palindrome (26556644665562).

The spelling of 14404113525121 in words is "fourteen trillion, four hundred four billion, one hundred thirteen million, five hundred twenty-five thousand, one hundred twenty-one".