14404323121 has 4 divisors (see below), whose sum is σ = 14433190000. Its totient is φ = 14375456244.

The previous prime is 14404323119. The next prime is 14404323133. The reversal of 14404323121 is 12132340441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14404323121 - 2¹ = 14404323119 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14404323151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14432691 + ... + 14433688.

It is an arithmetic number, because the mean of its divisors is an integer number (3608297500).

Almost surely, 2^14404323121 is an apocalyptic number.

It is an amenable number.

14404323121 is a deficient number, since it is larger than the sum of its proper divisors (28866879).

14404323121 is an equidigital number, since it uses as much as digits as its factorization.

14404323121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28866878.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14404323121 its reverse (12132340441), we get a palindrome (26536663562).

The spelling of 14404323121 in words is "fourteen billion, four hundred four million, three hundred twenty-three thousand, one hundred twenty-one".