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1440447302443 is a prime number
BaseRepresentation
bin10100111101100001010…
…110011000101100101011
312002201001020201122120111
4110331201112120230223
5142100014002134233
63021422104435151
7206032425023422
oct24754126305453
95081036648514
101440447302443
11505987a4a276
121b3202a78ab7
13a5aab550326
144da0a3722b9
1527709050acd
hex14f61598b2b

1440447302443 has 2 divisors, whose sum is σ = 1440447302444. Its totient is φ = 1440447302442.

The previous prime is 1440447302419. The next prime is 1440447302447. The reversal of 1440447302443 is 3442037440441.

It is a strong prime.

It is an emirp because it is prime and its reverse (3442037440441) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1440447302443 is a prime.

It is a super-2 number, since 2×14404473024432 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1440447302396 and 1440447302405.

It is not a weakly prime, because it can be changed into another prime (1440447302447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720223651221 + 720223651222.

It is an arithmetic number, because the mean of its divisors is an integer number (720223651222).

Almost surely, 21440447302443 is an apocalyptic number.

1440447302443 is a deficient number, since it is larger than the sum of its proper divisors (1).

1440447302443 is an equidigital number, since it uses as much as digits as its factorization.

1440447302443 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 516096, while the sum is 40.

The spelling of 1440447302443 in words is "one trillion, four hundred forty billion, four hundred forty-seven million, three hundred two thousand, four hundred forty-three".