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1440447302513 is a prime number
BaseRepresentation
bin10100111101100001010…
…110011000101101110001
312002201001020201122200002
4110331201112120231301
5142100014002140023
63021422104435345
7206032425023552
oct24754126305561
95081036648602
101440447302513
11505987a4a32a
121b3202a78b55
13a5aab55037b
144da0a372329
1527709050b28
hex14f61598b71

1440447302513 has 2 divisors, whose sum is σ = 1440447302514. Its totient is φ = 1440447302512.

The previous prime is 1440447302447. The next prime is 1440447302521. The reversal of 1440447302513 is 3152037440441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1439587229584 + 860072929 = 1199828^2 + 29327^2 .

It is a cyclic number.

It is not a de Polignac number, because 1440447302513 - 218 = 1440447040369 is a prime.

It is a super-4 number, since 4×14404473025134 (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1440447302563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720223651256 + 720223651257.

It is an arithmetic number, because the mean of its divisors is an integer number (720223651257).

Almost surely, 21440447302513 is an apocalyptic number.

It is an amenable number.

1440447302513 is a deficient number, since it is larger than the sum of its proper divisors (1).

1440447302513 is an equidigital number, since it uses as much as digits as its factorization.

1440447302513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 161280, while the sum is 38.

The spelling of 1440447302513 in words is "one trillion, four hundred forty billion, four hundred forty-seven million, three hundred two thousand, five hundred thirteen".