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14410221113443 = 52399672764423
BaseRepresentation
bin1101000110110010010000…
…0111000101000001100011
31220000121022002022200111111
43101230210013011001203
53342044113101112233
650351544133124151
73015050466315121
oct321544407050143
956017262280444
1014410221113443
114656382165881
121748969a89657
13806b55019bbc
1437b65bcb0911
1519ec99cceacd
hexd1b241c5063

14410221113443 has 8 divisors (see below), whose sum is σ = 14439227898368. Its totient is φ = 14381219878344.

The previous prime is 14410221113429. The next prime is 14410221113521. The reversal of 14410221113443 is 34431112201441.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14410221113443 - 213 = 14410221105251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14410221113243) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3830530 + ... + 6594952.

It is an arithmetic number, because the mean of its divisors is an integer number (1804903487296).

Almost surely, 214410221113443 is an apocalyptic number.

14410221113443 is a deficient number, since it is larger than the sum of its proper divisors (29006784925).

14410221113443 is an equidigital number, since it uses as much as digits as its factorization.

14410221113443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2774913.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 14410221113443 its reverse (34431112201441), we get a palindrome (48841333314884).

The spelling of 14410221113443 in words is "fourteen trillion, four hundred ten billion, two hundred twenty-one million, one hundred thirteen thousand, four hundred forty-three".

Divisors: 1 523 9967 2764423 5212741 1445793229 27553004041 14410221113443