144104340120001 has 4 divisors (see below), whose sum is σ = 144104396052400. Its totient is φ = 144104284187604.

The previous prime is 144104340119963. The next prime is 144104340120023. The reversal of 144104340120001 is 100021043401441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 144104340120001 - 2³⁵ = 144069980381633 is a prime.

It is a super-3 number, since 3×144104340120001³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144104340120031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23905011 + ... + 29319928.

It is an arithmetic number, because the mean of its divisors is an integer number (36026099013100).

Almost surely, 2^{144104340120001} is an apocalyptic number.

It is an amenable number.

144104340120001 is a deficient number, since it is larger than the sum of its proper divisors (55932399).

144104340120001 is an equidigital number, since it uses as much as digits as its factorization.

144104340120001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55932398.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 144104340120001 its reverse (100021043401441), we get a palindrome (244125383521442).

The spelling of 144104340120001 in words is "one hundred forty-four trillion, one hundred four billion, three hundred forty million, one hundred twenty thousand, one".