Base | Representation |
---|---|
bin | 1101000110110101001010… |
… | …0011110111010010111011 |
3 | 1220000200022101201010012221 |
4 | 3101231102203313102323 |
5 | 3342102212101130243 |
6 | 50352153332144511 |
7 | 3015106011246445 |
oct | 321552243672273 |
9 | 56020271633187 |
10 | 14411000411323 |
11 | 465674204690a |
12 | 1748b46a68137 |
13 | 806c4a601bc9 |
14 | 37b6d35ab495 |
15 | 19ece3417bed |
hex | d1b528f74bb |
14411000411323 has 2 divisors, whose sum is σ = 14411000411324. Its totient is φ = 14411000411322.
The previous prime is 14411000411317. The next prime is 14411000411377. The reversal of 14411000411323 is 32311400011441.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14411000411323 is a prime.
It is a super-2 number, since 2×144110004113232 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14411000411383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7205500205661 + 7205500205662.
It is an arithmetic number, because the mean of its divisors is an integer number (7205500205662).
Almost surely, 214411000411323 is an apocalyptic number.
14411000411323 is a deficient number, since it is larger than the sum of its proper divisors (1).
14411000411323 is an equidigital number, since it uses as much as digits as its factorization.
14411000411323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 14411000411323 its reverse (32311400011441), we get a palindrome (46722400422764).
The spelling of 14411000411323 in words is "fourteen trillion, four hundred eleven billion, four hundred eleven thousand, three hundred twenty-three".
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