Base | Representation |
---|---|
bin | 100000110001001110001110… |
… | …000000001100000011011011 |
3 | 200220021201221021222111102021 |
4 | 200301032032000030003123 |
5 | 122342230240032000243 |
6 | 1230303452452315311 |
7 | 42233220125524354 |
oct | 4061161600140333 |
9 | 626251837874367 |
10 | 144120010031323 |
11 | 41a14a53509687 |
12 | 141b750b912b37 |
13 | 62555c67c6391 |
14 | 2783635024d2b |
15 | 119dd5b27e6ed |
hex | 83138e00c0db |
144120010031323 has 2 divisors, whose sum is σ = 144120010031324. Its totient is φ = 144120010031322.
The previous prime is 144120010031297. The next prime is 144120010031363. The reversal of 144120010031323 is 323130010021441.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 144120010031323 - 225 = 144119976476891 is a prime.
It is a super-2 number, since 2×1441200100313232 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (144120010031363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72060005015661 + 72060005015662.
It is an arithmetic number, because the mean of its divisors is an integer number (72060005015662).
Almost surely, 2144120010031323 is an apocalyptic number.
144120010031323 is a deficient number, since it is larger than the sum of its proper divisors (1).
144120010031323 is an equidigital number, since it uses as much as digits as its factorization.
144120010031323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 144120010031323 its reverse (323130010021441), we get a palindrome (467250020052764).
The spelling of 144120010031323 in words is "one hundred forty-four trillion, one hundred twenty billion, ten million, thirty-one thousand, three hundred twenty-three".
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