Base | Representation |
---|---|
bin | 100000110001010010010110… |
… | …010010011111000111001011 |
3 | 200220022011101022022002210222 |
4 | 200301102112102133013023 |
5 | 122342313330131404003 |
6 | 1230305504444100255 |
7 | 42233435035663556 |
oct | 4061222622370713 |
9 | 626264338262728 |
10 | 144124444013003 |
11 | 41a16919368753 |
12 | 141b834883468b |
13 | 6255b522c678c |
14 | 2783935c6769d |
15 | 119e01a67bc38 |
hex | 83149649f1cb |
144124444013003 has 8 divisors (see below), whose sum is σ = 145744423460640. Its totient is φ = 142504477980480.
The previous prime is 144124444012973. The next prime is 144124444013041. The reversal of 144124444013003 is 300310444421441.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 144124444013003 - 212 = 144124444008907 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (144124444013083) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19093493 + ... + 25550153.
It is an arithmetic number, because the mean of its divisors is an integer number (18218052932580).
Almost surely, 2144124444013003 is an apocalyptic number.
144124444013003 is a deficient number, since it is larger than the sum of its proper divisors (1619979447637).
144124444013003 is an equidigital number, since it uses as much as digits as its factorization.
144124444013003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6707557.
The product of its (nonzero) digits is 73728, while the sum is 35.
Adding to 144124444013003 its reverse (300310444421441), we get a palindrome (444434888434444).
The spelling of 144124444013003 in words is "one hundred forty-four trillion, one hundred twenty-four billion, four hundred forty-four million, thirteen thousand, three".
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