Base | Representation |
---|---|
bin | 100000110001010111100100… |
… | …000110010100000011100011 |
3 | 200220022200211121102212010220 |
4 | 200301113210012110003203 |
5 | 122342411312332142011 |
6 | 1230312232304054123 |
7 | 42234023601412041 |
oct | 4061274406240343 |
9 | 626280747385126 |
10 | 144130044412131 |
11 | 41a19232676488 |
12 | 141b9450304343 |
13 | 625653566080b |
14 | 2783d07977391 |
15 | 119e24717e506 |
hex | 8315e41940e3 |
144130044412131 has 8 divisors (see below), whose sum is σ = 193019971372224. Its totient is φ = 95663406863400.
The previous prime is 144130044412111. The next prime is 144130044412163. The reversal of 144130044412131 is 131214440031441.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 144130044412131 - 25 = 144130044412099 is a prime.
It is a super-3 number, since 3×1441300444121313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 144130044412092 and 144130044412101.
It is not an unprimeable number, because it can be changed into a prime (144130044412111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 105822352045 + ... + 105822353406.
It is an arithmetic number, because the mean of its divisors is an integer number (24127496421528).
Almost surely, 2144130044412131 is an apocalyptic number.
144130044412131 is a deficient number, since it is larger than the sum of its proper divisors (48889926960093).
144130044412131 is a wasteful number, since it uses less digits than its factorization.
144130044412131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 211644705681.
The product of its (nonzero) digits is 18432, while the sum is 33.
Adding to 144130044412131 its reverse (131214440031441), we get a palindrome (275344484443572).
The spelling of 144130044412131 in words is "one hundred forty-four trillion, one hundred thirty billion, forty-four million, four hundred twelve thousand, one hundred thirty-one".
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