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14413052102203 = 51145728180379
BaseRepresentation
bin1101000110111100110011…
…0110011100011000111011
31220000212121101022211000001
43101233030312130120323
53342120412314232303
650353133103053431
73015210603320506
oct321571466343073
956025541284001
1014413052102203
1146575a5189607
121749419ba1277
138071b66a7191
1437b849c8013d
1519edb35db31d
hexd1bccd9c63b

14413052102203 has 4 divisors (see below), whose sum is σ = 14413080794040. Its totient is φ = 14413023410368.

The previous prime is 14413052102177. The next prime is 14413052102249. The reversal of 14413052102203 is 30220125031441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14413052102203 - 213 = 14413052094011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14413052102903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13578733 + ... + 14601646.

It is an arithmetic number, because the mean of its divisors is an integer number (3603270198510).

Almost surely, 214413052102203 is an apocalyptic number.

14413052102203 is a deficient number, since it is larger than the sum of its proper divisors (28691837).

14413052102203 is an equidigital number, since it uses as much as digits as its factorization.

14413052102203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28691836.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 14413052102203 its reverse (30220125031441), we get a palindrome (44633177133644).

The spelling of 14413052102203 in words is "fourteen trillion, four hundred thirteen billion, fifty-two million, one hundred two thousand, two hundred three".

Divisors: 1 511457 28180379 14413052102203