Base | Representation |
---|---|
bin | 100000110001011001011111… |
… | …011001101111101000101001 |
3 | 200220022220011210001021002002 |
4 | 200301121133121233220221 |
5 | 122342430031423302101 |
6 | 1230313213443220345 |
7 | 42234126061116653 |
oct | 4061313731575051 |
9 | 626286153037062 |
10 | 144132113103401 |
11 | 41a1a0a436a895 |
12 | 141b99290776b5 |
13 | 62567a5108aa7 |
14 | 27840625d36d3 |
15 | 119e318aaed6b |
hex | 83165f66fa29 |
144132113103401 has 2 divisors, whose sum is σ = 144132113103402. Its totient is φ = 144132113103400.
The previous prime is 144132113103383. The next prime is 144132113103427. The reversal of 144132113103401 is 104301311231441.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 113360418997225 + 30771694106176 = 10647085^2 + 5547224^2 .
It is a cyclic number.
It is not a de Polignac number, because 144132113103401 - 226 = 144132045994537 is a prime.
It is not a weakly prime, because it can be changed into another prime (144132113102401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72066056551700 + 72066056551701.
It is an arithmetic number, because the mean of its divisors is an integer number (72066056551701).
Almost surely, 2144132113103401 is an apocalyptic number.
It is an amenable number.
144132113103401 is a deficient number, since it is larger than the sum of its proper divisors (1).
144132113103401 is an equidigital number, since it uses as much as digits as its factorization.
144132113103401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 29.
Adding to 144132113103401 its reverse (104301311231441), we get a palindrome (248433424334842).
The spelling of 144132113103401 in words is "one hundred forty-four trillion, one hundred thirty-two billion, one hundred thirteen million, one hundred three thousand, four hundred one".
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