Base | Representation |
---|---|
bin | 1000011000111100000… |
… | …1011111110101100011 |
3 | 111210000220112011022122 |
4 | 2012033001133311203 |
5 | 4330141131031303 |
6 | 150114120054455 |
7 | 13261522104053 |
oct | 2061701376543 |
9 | 453026464278 |
10 | 144133455203 |
11 | 5614363a221 |
12 | 23b2600442b |
13 | 1079003ba8a |
14 | 6d945a1563 |
15 | 3b38a58e38 |
hex | 218f05fd63 |
144133455203 has 2 divisors, whose sum is σ = 144133455204. Its totient is φ = 144133455202.
The previous prime is 144133455187. The next prime is 144133455209. The reversal of 144133455203 is 302554331441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144133455203 - 24 = 144133455187 is a prime.
It is not a weakly prime, because it can be changed into another prime (144133455209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72066727601 + 72066727602.
It is an arithmetic number, because the mean of its divisors is an integer number (72066727602).
Almost surely, 2144133455203 is an apocalyptic number.
144133455203 is a deficient number, since it is larger than the sum of its proper divisors (1).
144133455203 is an equidigital number, since it uses as much as digits as its factorization.
144133455203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 144133455203 its reverse (302554331441), we get a palindrome (446687786644).
The spelling of 144133455203 in words is "one hundred forty-four billion, one hundred thirty-three million, four hundred fifty-five thousand, two hundred three".
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