144134212131433 has 2 divisors, whose sum is σ = 144134212131434. Its totient is φ = 144134212131432.

The previous prime is 144134212131383. The next prime is 144134212131467. The reversal of 144134212131433 is 334131212431441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 140630378477824 + 3503833653609 = 11858768^2 + 1871853^2 .

It is an emirp because it is prime and its reverse (334131212431441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 144134212131433 - 2⁹ = 144134212130921 is a prime.

It is a super-2 number, since 2×144134212131433² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 144134212131392 and 144134212131401.

It is not a weakly prime, because it can be changed into another prime (144134212141433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72067106065716 + 72067106065717.

It is an arithmetic number, because the mean of its divisors is an integer number (72067106065717).

Almost surely, 2^{144134212131433} is an apocalyptic number.

It is an amenable number.

144134212131433 is a deficient number, since it is larger than the sum of its proper divisors (1).

144134212131433 is an equidigital number, since it uses as much as digits as its factorization.

144134212131433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 82944, while the sum is 37.

Adding to 144134212131433 its reverse (334131212431441), we get a palindrome (478265424562874).

The spelling of 144134212131433 in words is "one hundred forty-four trillion, one hundred thirty-four billion, two hundred twelve million, one hundred thirty-one thousand, four hundred thirty-three".