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14415005244307 is a prime number
BaseRepresentation
bin1101000111000100000101…
…0001000101101110010011
31220001001122111111201021111
43101301001101011232103
53342133412320304212
650354054553434151
73015310160622403
oct321610121055623
956031574451244
1014415005244307
114658407731138
12174988410b957
13807438226375
1437b99341c803
1519ee79ce4ea7
hexd1c41445b93

14415005244307 has 2 divisors, whose sum is σ = 14415005244308. Its totient is φ = 14415005244306.

The previous prime is 14415005244217. The next prime is 14415005244313. The reversal of 14415005244307 is 70344250051441.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14415005244307 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14415005244307.

It is not a weakly prime, because it can be changed into another prime (14415005244377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7207502622153 + 7207502622154.

It is an arithmetic number, because the mean of its divisors is an integer number (7207502622154).

Almost surely, 214415005244307 is an apocalyptic number.

14415005244307 is a deficient number, since it is larger than the sum of its proper divisors (1).

14415005244307 is an equidigital number, since it uses as much as digits as its factorization.

14415005244307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 268800, while the sum is 40.

Adding to 14415005244307 its reverse (70344250051441), we get a palindrome (84759255295748).

The spelling of 14415005244307 in words is "fourteen trillion, four hundred fifteen billion, five million, two hundred forty-four thousand, three hundred seven".