Base | Representation |
---|---|
bin | 11010110110011110… |
… | …01010100111100001 |
3 | 1101012122111120100102 |
4 | 31123033022213201 |
5 | 214010343313233 |
6 | 10342240232145 |
7 | 1020142420364 |
oct | 153317124741 |
9 | 41178446312 |
10 | 14415604193 |
11 | 6128261881 |
12 | 296390b655 |
13 | 1489754b13 |
14 | 9aa7800db |
15 | 59587a1e8 |
hex | 35b3ca9e1 |
14415604193 has 2 divisors, whose sum is σ = 14415604194. Its totient is φ = 14415604192.
The previous prime is 14415604139. The next prime is 14415604199. The reversal of 14415604193 is 39140651441.
Together with previous prime (14415604139) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8829985024 + 5585619169 = 93968^2 + 74737^2 .
It is a cyclic number.
It is not a de Polignac number, because 14415604193 - 212 = 14415600097 is a prime.
It is not a weakly prime, because it can be changed into another prime (14415604199) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7207802096 + 7207802097.
It is an arithmetic number, because the mean of its divisors is an integer number (7207802097).
Almost surely, 214415604193 is an apocalyptic number.
It is an amenable number.
14415604193 is a deficient number, since it is larger than the sum of its proper divisors (1).
14415604193 is an equidigital number, since it uses as much as digits as its factorization.
14415604193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 38.
The spelling of 14415604193 in words is "fourteen billion, four hundred fifteen million, six hundred four thousand, one hundred ninety-three".
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