Base | Representation |
---|---|
bin | 1000011001001110111… |
… | …1001001110100110011 |
3 | 111210020102022201000120 |
4 | 2012103233021310303 |
5 | 4330321402020111 |
6 | 150130023021323 |
7 | 13263502205154 |
oct | 2062357116463 |
9 | 453212281016 |
10 | 144212532531 |
11 | 56184240191 |
12 | 23b4859a843 |
13 | 107a35381b2 |
14 | 6da0ca792b |
15 | 3b40979406 |
hex | 2193bc9d33 |
144212532531 has 4 divisors (see below), whose sum is σ = 192283376712. Its totient is φ = 96141688352.
The previous prime is 144212532517. The next prime is 144212532559. The reversal of 144212532531 is 135235212441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 144212532531 - 27 = 144212532403 is a prime.
It is a super-2 number, since 2×1442125325312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 144212532492 and 144212532501.
It is not an unprimeable number, because it can be changed into a prime (144212539531) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24035422086 + ... + 24035422091.
It is an arithmetic number, because the mean of its divisors is an integer number (48070844178).
Almost surely, 2144212532531 is an apocalyptic number.
144212532531 is a deficient number, since it is larger than the sum of its proper divisors (48070844181).
144212532531 is an equidigital number, since it uses as much as digits as its factorization.
144212532531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48070844180.
The product of its digits is 28800, while the sum is 33.
Adding to 144212532531 its reverse (135235212441), we get a palindrome (279447744972).
The spelling of 144212532531 in words is "one hundred forty-four billion, two hundred twelve million, five hundred thirty-two thousand, five hundred thirty-one".
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