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14423043120113 is a prime number
BaseRepresentation
bin1101000111100010000001…
…0111001001101111110001
31220001211101200012010000102
43101320200113021233301
53342301343014320423
650401504325202145
73016013311502555
oct321704027115761
956054350163012
1014423043120113
114660861919201
12174b347b60355
1380811956b1b4
1437c116b45865
151a029a7c2c28
hexd1e205c9bf1

14423043120113 has 2 divisors, whose sum is σ = 14423043120114. Its totient is φ = 14423043120112.

The previous prime is 14423043120011. The next prime is 14423043120163. The reversal of 14423043120113 is 31102134032441.

14423043120113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12294195790864 + 2128847329249 = 3506308^2 + 1459057^2 .

It is a cyclic number.

It is not a de Polignac number, because 14423043120113 - 228 = 14422774684657 is a prime.

It is not a weakly prime, because it can be changed into another prime (14423043120163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7211521560056 + 7211521560057.

It is an arithmetic number, because the mean of its divisors is an integer number (7211521560057).

Almost surely, 214423043120113 is an apocalyptic number.

It is an amenable number.

14423043120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14423043120113 is an equidigital number, since it uses as much as digits as its factorization.

14423043120113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 14423043120113 its reverse (31102134032441), we get a palindrome (45525177152554).

The spelling of 14423043120113 in words is "fourteen trillion, four hundred twenty-three billion, forty-three million, one hundred twenty thousand, one hundred thirteen".