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14423343321203 is a prime number
BaseRepresentation
bin1101000111100011001001…
…0000010101000001110011
31220001212011121001220111022
43101320302100111001303
53342303001342234303
650401554211410055
73016023615250445
oct321706220250163
956055147056438
1014423343321203
1146609a631a783
12174b4105b392b
1380816680968b
1437c14496c495
151a02b6d21438
hexd1e32415073

14423343321203 has 2 divisors, whose sum is σ = 14423343321204. Its totient is φ = 14423343321202.

The previous prime is 14423343321197. The next prime is 14423343321229. The reversal of 14423343321203 is 30212334332441.

It is a weak prime.

It is an emirp because it is prime and its reverse (30212334332441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14423343321203 - 226 = 14423276212339 is a prime.

It is a super-2 number, since 2×144233433212032 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14423343321293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7211671660601 + 7211671660602.

It is an arithmetic number, because the mean of its divisors is an integer number (7211671660602).

Almost surely, 214423343321203 is an apocalyptic number.

14423343321203 is a deficient number, since it is larger than the sum of its proper divisors (1).

14423343321203 is an equidigital number, since it uses as much as digits as its factorization.

14423343321203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 14423343321203 its reverse (30212334332441), we get a palindrome (44635677653644).

The spelling of 14423343321203 in words is "fourteen trillion, four hundred twenty-three billion, three hundred forty-three million, three hundred twenty-one thousand, two hundred three".