Base | Representation |
---|---|
bin | 100000110010111111000000… |
… | …010111111110101010001011 |
3 | 200220201022112020212100102111 |
4 | 200302333000113332222023 |
5 | 122401221300214304003 |
6 | 1230435241511243151 |
7 | 42245035163220343 |
oct | 4062770027765213 |
9 | 626638466770374 |
10 | 144241114213003 |
11 | 41a61349684845 |
12 | 14216a893794b7 |
13 | 6263b56696892 |
14 | 2789442c77d23 |
15 | 11a2098144e6d |
hex | 832fc05fea8b |
144241114213003 has 2 divisors, whose sum is σ = 144241114213004. Its totient is φ = 144241114213002.
The previous prime is 144241114212931. The next prime is 144241114213043. The reversal of 144241114213003 is 300312411142441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144241114213003 - 217 = 144241114081931 is a prime.
It is not a weakly prime, because it can be changed into another prime (144241114213043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72120557106501 + 72120557106502.
It is an arithmetic number, because the mean of its divisors is an integer number (72120557106502).
Almost surely, 2144241114213003 is an apocalyptic number.
144241114213003 is a deficient number, since it is larger than the sum of its proper divisors (1).
144241114213003 is an equidigital number, since it uses as much as digits as its factorization.
144241114213003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 144241114213003 its reverse (300312411142441), we get a palindrome (444553525355444).
The spelling of 144241114213003 in words is "one hundred forty-four trillion, two hundred forty-one billion, one hundred fourteen million, two hundred thirteen thousand, three".
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